有限数学示例

$[\begin{array}{c} 2 & 3 & 4 \\ 3 & 4 & 3 \end{array}]$

解题步骤 1

Multiply each element of $R_{1}$ by $\frac{1}{2}$ to make the entry at $1, 1$ a $1$ .

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解题步骤 1.1

Multiply each element of $R_{1}$ by $\frac{1}{2}$ to make the entry at $1, 1$ a $1$ .

$[\begin{array}{c} \frac{2}{2} & \frac{3}{2} & \frac{4}{2} \\ 3 & 4 & 3 \end{array}]$

解题步骤 1.2

化简 $R_{1}$ 。

$[\begin{array}{c} 1 & \frac{3}{2} & 2 \\ 3 & 4 & 3 \end{array}]$

解题步骤 2

Perform the row operation $R_{2} = R_{2} - 3 R_{1}$ to make the entry at $2, 1$ a $0$ .

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解题步骤 2.1

Perform the row operation $R_{2} = R_{2} - 3 R_{1}$ to make the entry at $2, 1$ a $0$ .

$[\begin{array}{c} 1 & \frac{3}{2} & 2 \\ 3 - 3 \cdot 1 & 4 - 3 (\frac{3}{2}) & 3 - 3 \cdot 2 \end{array}]$

解题步骤 2.2

化简 $R_{2}$ 。

$[\begin{array}{c} 1 & \frac{3}{2} & 2 \\ 0 & - \frac{1}{2} & - 3 \end{array}]$

解题步骤 3

Multiply each element of $R_{2}$ by $- 2$ to make the entry at $2, 2$ a $1$ .

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解题步骤 3.1

Multiply each element of $R_{2}$ by $- 2$ to make the entry at $2, 2$ a $1$ .

$[\begin{array}{c} 1 & \frac{3}{2} & 2 \\ - 2 \cdot 0 & - 2 (- \frac{1}{2}) & - 2 \cdot - 3 \end{array}]$

解题步骤 3.2

化简 $R_{2}$ 。

$[\begin{array}{c} 1 & \frac{3}{2} & 2 \\ 0 & 1 & 6 \end{array}]$

解题步骤 4

Perform the row operation $R_{1} = R_{1} - \frac{3}{2} R_{2}$ to make the entry at $1, 2$ a $0$ .

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解题步骤 4.1

Perform the row operation $R_{1} = R_{1} - \frac{3}{2} R_{2}$ to make the entry at $1, 2$ a $0$ .

$[\begin{array}{c} 1 - \frac{3}{2} \cdot 0 & \frac{3}{2} - \frac{3}{2} \cdot 1 & 2 - \frac{3}{2} \cdot 6 \\ 0 & 1 & 6 \end{array}]$

解题步骤 4.2

化简 $R_{1}$ 。

$[\begin{array}{c} 1 & 0 & - 7 \\ 0 & 1 & 6 \end{array}]$

有限数学 示例